MCQ
Correct order of basicity of various nitrogen in $LSD$ is


- A$1 > 2 > 3$
- ✓$2 > 1 > 3$
- C$ 2 > 3 > 1$
- D$3 > 2 > 1$

Nitrogen $3$ is least basic because the lone pair on $N$ is in resonance with $C = O$ double bond of carbonyl group.
$1$ is less basic than $2$ because in $1$ , the lone pair on $N$ is in resonance with benzene ring as well as with the double bond.
Correct order of basicity of various nitrogen in LSD (lysergic acid diethylamide) is $2\,>\,1\,>\,3$.
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$[Image]$
the number of $sp ^{2}$ hybridised carbon (s) in compound ' $X$ ' is $.....$
$\mathrm{A}_{2}(\mathrm{g})+\mathrm{B}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{X}_{2}(\mathrm{g}) \Delta_{r} \mathrm{H}=-\mathrm{X} \mathrm{kJ} ?$

