MCQ
Correct order of bond angle in given species is
- A$SiO_4^{4-} > PCl_3 > NCl_3 > SbH_3 > H_2Te$
- B$SiO_4^{4-} > NCl_3 > PCl_3 > SbH_3 > H_2Te$
- ✓$SiO_4^{4-} > H_2Te > SbH_3 > PCl_3 > NCl_3$
- D$NCl_3 > PCl_3 > Si_4^{4-} > SbH_3 > H_2Te$
$Cl_2 (g) + 2H_2O (l) \to HCl(aq) + HOCl$
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| Complexes | No. of unpaired electron | ||
| $A$ | $[CrF_6]^{-4}$ | $P$ | $5$ |
| $B$ | $[MnF_6]^{-4}$ | $Q$ | $2$ |
| $C$ | $[Cr(CN)_6]^{-4}$ | $R$ | $1$ |
| $D$ | $[Mn(CN)_6]^{-4}$ | $S$ | $4$ |