MCQ
Correct order of bond angle is
- ✓$OF_2 < H_2O < NH_3 < Cl_2O$
- B$OF_2 < NH_3 < Cl_2O < H_2O$
- C$OF_2 < Cl_2O < H_2O < NH_3$
- D$Cl_2O < OF_2 < H_2O < NH_3$
$\mathrm{NH}_{3} \Rightarrow 107^{o}, \mathrm{OCl}_{2} \Rightarrow>109.5^{o}$
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$\Delta_{ I } G ^{\circ}=-9.478\, kJ\, mol ^{-1}$
If we start the reaction in a closed container at $495\, K$ with $22$ millimoles of $A ,$ the amount of $B$ is the equilibrium mixture is millimoles ..............
(Round off to the Nearest Integer).
$\left[ R =8.314 J mol ^{-1} K ^{-1} ; \ell n 10=2.303\right]$