MCQ
Correct order of extent of overlapping is
  • A
    $1s-1s < 2s-2s < 2s-2p$
  • B
    $2p-2p\, (axial) < 2p-2p\, (colateral)$
  • $1s-1s > 2p-2p\, (axial) > 2s-2p > 2s-2s$
  • D
    $1s-1s > 2s-2p > 2s-2s > 2p-2p\, (axial)$

Answer

Correct option: C.
$1s-1s > 2p-2p\, (axial) > 2s-2p > 2s-2s$
c

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Assertion : An orbital designated by $n = 3, l = 1$ has double dumb-bell shape.
Reason : It belongs to $p-$ subshell.
Calculate the weight of non-volatile solute having molecular weight $40,$ which is dissolved in $57\,g$ octane to reduce its vapour pressure by $20\%$ .......... $g$.
$(CH_3)_2C = CHCH_3 + NOBr \to $ product. The structure of the product is
 Product $A$ is major
Given the data at $25\,^o C$

$Ag+ I^- \rightarrow AgI +e^-,$  $E^o = 0.152\, V$

$Ag \rightarrow Ag^+ +e^-,$    $E^o =-0.800\, V$

What is the value of log $K_{sp}$ for $AgI$ ? $(2. 303\, RT/F= 0. 059\, V)$

Match the following:
Column $I$ Column $II$
$(A)$ $\mathrm{CH}_3-\mathrm{CHBr}-\mathrm{CD}_3$ on treatment with alc. $\mathrm{KOH}$ gives $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CD}_3$ as a major product. $(P)$ $E1$ reaction
$(B)$ $\mathrm{Ph}-\mathrm{CHBr}-\mathrm{CH}_3$ reacts faster than $\mathrm{Ph}-\mathrm{CHBr}-\mathrm{CD}_3$. $(Q)$ $E2$ reaction
$(C)$ $\mathrm{Ph}-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{Br}$ on treatment with $\mathrm{C}_2 \mathrm{H}_5 \mathrm{OD} / \mathrm{C}_2 \mathrm{H}_5 \mathrm{O}^{-}$ gives $\mathrm{Ph}-\mathrm{CD}=\mathrm{CH}_2$ as the major product. $(R)$ $E1$ cb reaction
$(D)$ $\mathrm{PhCH}_2 \mathrm{CH}_2 \mathrm{Br}$ and $\mathrm{PhCD}_2 \mathrm{CH}_2 \mathrm{Br}$ react with same rate. $(S)$ First order reaction
1.24 g of $\mathrm{AX}_{2}$ (molar mass $124 \mathrm{~g} \mathrm{~mol}^{-1}$ ) is dissolved in 1 kg of water to form a solution with boiling point of $100.0156^{\circ} \mathrm{C}$, while 25.4 g of $\mathrm{AY}_{2}$ (molar mass $250 \mathrm{~g} \mathrm{~mol}^{-1}$ ) in 2 kg of water constitutes a solution with a boiling point of $100.0260^{\circ} \mathrm{C}$. $\mathrm{K}_{\mathrm{b}}\left(\mathrm{H}_{2} \mathrm{O}\right)=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ Which of the following is correct ?
Which of the following arrangement for the three halogens $Cl,$ $Br$ and $I$ when placed in the order of their increasing electron affinity is correct
If $C + {O_2} \to C{O_2} + 94.2\,kcal$

${H_2} + \frac{1}{2}{O_2} \to \,{H_2}O + 68.3\,kcal$

$C{H_4} + 2{O_2}\, \to \,C{O_2} + 2{H_2}O + 210.8\,kcal$ Then the possible heat of methane will be.....$ kcal$

From given pair of compounds, in which first will undergo $S_N2$ faster :