- ✓$BF_3 < BCl_3 < BBr_3 < BI_3$
- B$BF_3 > BCl_3 > BBr_3 > BI_3$
- C$BF_3 = BCl_3 = BBr_3 = BI_3$
- D$BF_3 > BCl_3 < BBr_3 > BI_3$
(ii) Size of halides increase down the group, hence the ability of back bonding decreases making the molecule more acidic.
Hence, correct order of Lewis acid for boron-halides is $\mathrm{Bl}_{3}>\mathrm{BBr}_{3}>\mathrm{BCl}_{3}>\mathrm{BF}_{3}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Rate of the reaction is the highest for
$2 \mathrm{~A}_{(\mathrm{g})}+\mathrm{B}_{(\mathrm{g})} \rightarrow \mathrm{C}_{(\mathrm{g})}$
The initial rate of the reaction is recorded as $r_1$ when the reaction starts with $1.5 \mathrm{~atm}$ pressure of $\mathrm{A}$ and $0.7 \mathrm{~atm}$ pressure of B. After some time, the rate $r_2$ is recorded when the pressure of $C$ becomes $0.5 \mathrm{~atm}$. The ratio $r_1: r_2$ is $\qquad$ $\times 10^{-1}$.
(Nearest integer)
