MCQ
Correct statement about product is
  • A
    It is optically inactive
  • It is optically active and having one less carbon than reactant
  • C
    Product do not give isocyanide test
  • D
    Product is carboxylic acid

Answer

Correct option: B.
It is optically active and having one less carbon than reactant
b
It is Hoffman Bromamide degradation

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Similar questions

Consider th following four reactions:

$(I)$ $\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - Cl} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}\xrightarrow[{5\% \,\,water}]{{95\% \,\,\,acetone}}\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - OH} \\ 
  | \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(II)$ $\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - Cl} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}\xrightarrow[{10\% \,\,water}]{{90\% \,\,\,acetone}}\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - OH} \\ 
  | \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(III)$ $\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - Cl} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}\xrightarrow[{20\% \,\,water}]{{80\% \,\,\,acetone}}\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - OH} \\ 
  | \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(IV)$ $\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - Cl} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}\xrightarrow{{100\% \,water}}\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - OH} \\ 
  | \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}$

Arrange these reactions in decreasing order of greater proportion of inverted product and select correct answer from the codes given below :

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