MCQ
Correct statement is
- A$N{H_4}Cl$ gives alkaline solution in water
- B$C{H_3}COONa$ gives acidic solution in water
- ✓$C{H_3}COOH$ is a weak acid
- D$N{H_4}OH$ is a strong base
$C{H_3}COOH⇌C{H_3}CO{O^ - } + {H^ + }$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
if $T_1 < T_2$ then $X$ and $Y$ respectively are
$\frac{1}{2}C{l_2}(g)\xrightarrow{{\frac{1}{2}{\Delta _{diss}}{H^\Theta }}}Cl(g)\xrightarrow{{{\Delta _{eg}}{H^\Theta }}}$ $C{l^ - }(g)\xrightarrow{{{\Delta _{Hyd}}{H^\Theta }}}C{l^ - }(aq)$
(using the data,
${{\Delta _{diss}}H_{C{l_2}}^\Theta } = 240\,kJ\,mol^{-1}, {{\Delta _{eg}}H_{C{l}}^\Theta }= -349 \,kJ\,mol^{-1},$${{\Delta _{Hyd}}H_{C{l}}^\Theta }= -381 \,kJ\,mol^{-1}$ ) will be ............. $\mathrm{kJ\,mol}^{-1}$
