MCQ
cos-1 $\left(\cos \frac{7 \pi}{6}\right) $ बराबर है
  • A
    $\frac{5 \pi}{6}$
  • B
    $\frac{7 \pi}{6}$
  • C
    $\frac{ \pi}{3}$
  • D
    $\frac{ \pi}{6}$

Answer

$\cos ^{-1}\left(\cos \frac{7 \pi}{6}\right)$ = $\cos ^{-1}\left[\cos \left(2 \pi-\frac{5 \pi}{6}\right)\right]$
जहाँ, $\frac{5 \pi}{6} \in[0, \pi] $ $ \therefore$ cos-1  $\left(\cos \frac{7 \pi}{6}\right)$ = cos-1 $ \left[\cos \left(\frac{5 \pi}{6}\right)\right]=\frac{5 \pi}{6}$ $[\because \cos (2 \pi-\theta)=\cos \theta]$
 

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