^ -1 ( 3 2 )= - Vidyadip

MCQ

$\cos ^{-1}\left(\frac{\sqrt{3}}{2}\right)=$

A
$\frac{\pi}{2}$
B
$\frac{\pi}{3}$
C
$\frac{\pi}{4}$
✓
$\frac{\pi}{6}$

✓

Answer

Correct option: D.

$\frac{\pi}{6}$

(d) : Let $\cos ^{-1} \frac{\sqrt{3}}{2}=\theta \Rightarrow \cos \theta=\frac{\sqrt{3}}{2}=\cos \frac{\pi}{6}$
$
\begin{array}{l}
\Rightarrow \quad \theta=\frac{\pi}{6} \in[0, \pi] \\
\therefore \quad \cos ^{-1}\left(\frac{\sqrt{3}}{2}\right)=\frac{\pi}{6}
\end{array}
$

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