MCQ
$\cos 2 \theta$ is not equal to
  • A
    $2 \cos ^2 \theta-1$
  • B
    $1-2 \sin ^2 \theta$
  • $\frac{1+\tan ^2 \theta}{1-\tan ^2 \theta}$
  • D
    $\frac{1-\tan ^2 \theta}{1+\tan ^2 \theta}$

Answer

Correct option: C.
$\frac{1+\tan ^2 \theta}{1-\tan ^2 \theta}$
(C)
$\cos 2 \theta=2 \cos ^2 \theta-1$
$=1-2 \sin ^2 \theta$
$=\frac{1-\tan ^2 \theta}{1+\tan ^2 \theta}$

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