MCQ
$\cos A +\cos \left(240^{\circ}+ A \right)+\cos \left(240^{\circ}- A \right)=$
  • A
    cos A
  • $0$
  • C
    $\sqrt{3} \sin A$
  • D
    $\sqrt{3} \cos A$

Answer

Correct option: B.
$0$
(B)
$\cos A +\cos \left(240^{\circ}+ A \right)+\cos \left(240^{\circ}- A \right)$
$=\cos A +2 \cos 240^{\circ} \cos A$
$=\cos A \left\{1+2 \cos \left(180^{\circ}+60^{\circ}\right)\right\}$
$=\cos A \left\{1+2\left(-\frac{1}{2}\right)\right\}$
= 0

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