Question
$\cos \left(\frac{\pi}{4}+x\right)+\cos \left(\frac{\pi}{4}-x\right)=\sqrt{2} \cos x$

Answer

L.H.S.
$\begin{aligned}
& =\cos \left(\frac{\pi}{4}+x\right)+\cos \left(\frac{\pi}{4}-x\right) \\
& =2 \cos \left(\frac{\frac{\pi}{4}+x+\frac{\pi}{4}-x}{2}\right) \cos \left(\frac{\frac{\pi}{4}+x-\left(\frac{\pi}{4}-x\right)}{2}\right) \\
& =2 \cos \frac{\pi}{4} \cos x \\
& =2\left(\frac{1}{\sqrt{2}}\right) \cos x \\
& =\sqrt{2} \cos x \\
& =\text { R.H.S. }
\end{aligned}$

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