^ -1 (1 x^2-1 )= _________ where x >1. - Vidyadip

MCQ

$\cot ^{-1}\left(\frac{1}{\sqrt{x^2-1}}\right)=$ _________ where $x >1.$

A
$\sec ^{-1} x$
B
$\sin ^{-1} x$
C
$\operatorname{cosec}^{-1} x$
D
$\cos ^{-1} x$

✓

Answer

SELF

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