cot 5^o -tan5^o -2 tan10^o -4 tan 20^o -8 cot40^o is equal to - Vidyadip

MCQ

$cot 5^o$ -$tan5^o$ -$2$ $tan10^o$ -$4$ $tan 20^o$ -$8$ $cot40^o$ is equal to

✓
$0$
B
$4\tan {40^o}$
C
$8\tan {40^o}$
D
$8\cot {40^o}$

✓

Answer

Correct option: A.

$0$

a
Use the relation $\cot \theta - \tan \theta = 2\cot 2\theta$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 11 - 3. trignometrical ratios,functions and identities→STD 11 - 3. trignometrical ratios,functions and identities — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

Consider the family of lines $x(a + b) + y = 1,$ where $a, b$ and $c$ are the roots of the equation $x^3 -3x^2 + x + \lambda= 0$ such that $c \in [1,2] .$ If the given family of lines makes triangle of area $'A'$ with coordinate axis, then maximum value of $'A'$ (in sq. units) will be -

If the product of three terms of $G.P.$ is $512$. If $8$ added to first and $6$ added to second term, so that number may be in $A.P.$, then the numbers are

The lines $y - y_1 = m (x - x_1) \pm a \,\sqrt {1\,\, + \,\,{m^2}} $ are tangents to the same circle . The radius of the circle is :

The opposite vertices of a square are $(1, 2)$ and $(3, 8)$, then the equation of a diagonal of the square passing through the point $(1, 2)$, is

Let $b, d>0$. The locus of all points $P(r, \theta)$ for which the line $P$ (where, $O$ is the origin) cuts the line $r \sin \theta=b$ in $Q$ such that $P Q=d$ is

If ${9 \over {(x - 1)\,{{(x + 2)}^2}}} = {A \over {x - 1}} + {B \over {x + 2}} + {C \over {{{(x + 2)}^2}}}$ then $A - B - C = $

The point which does not belong to the feasible region of the $\text{LPP:}$
Minimize: $\text{Z}=60\text{x}+10\text{y}$
subject to $3\text{x}+\text{y}\geq18$
$2\text{x}+2\text{y}\geq12$
$\text{x}+2\text{y}\geq10$
$\text{x,y}\geq0$ is.

If the coordinates of the points $A,\, B,\, C$ be $(-1, 5),\, (0, 0)$ and $(2, 2)$ respectively and $D$ be the middle point of $BC$, then the equation of the perpendicular drawn from $B$ to the line $AD$ is

If $(\text{x}+\text{iy})^{\frac{1}{3}}=\text{a}+\text{ib,}$ then $\frac{\text{x}}{\text{a}}+\frac{\text{y}}{\text{b}}=$

The number of six letter words that can be formed using the letters of the word "ASSIST" in which S's alternate with other letters is: