MCQ
$\frac{cot \theta - tan \theta}{1 - 2 sin^2 \theta} = ........$
- A$cosec 2\theta$
- B$\frac{1}{2}cosec 2\theta$
- ✓$2cosec 2\theta$
- D$2cosec \theta$
$\frac{cot \theta - tan \theta}{1 - 2 sin^2 \theta} = \frac{\frac{1}{tan \theta} - tan \theta}{cos 2 \theta}$
$= 2 \frac{1 - tan^2 \theta }{2 tan \theta.cos 2\theta }$
$= \frac{2}{tan 2 \theta . cos 2\theta}\ \left\{\frac{1 - tan^2 \theta}{2 tan \theta} = tan 2 \theta\right\}$
$= \frac{2 cos 2\theta}{sin 2 \theta . cos 2 \theta}$
$= \frac{2}{sin 2 \theta}$
$= 2 cosec 2 \theta $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.