MCQ
$CrO_3$ dissolves in aqueous $NaOH$ to give
- A$Cr_7O_7^{2-}$
- ✓$CrO_4^{2-}$
- C$Cr(OH)_3$
- D$Cr(OH)_2$
$\mathrm{CrO}_{3}+2 \mathrm{NaOH} \rightarrow \mathrm{Na}_{2} \mathrm{CrO}_{4}+\mathrm{H}_{2} \mathrm{O}$
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$C{S_2}(g) + 4{H_2}(g) \to C{H_4}(g) + 2{H_2}S(g)$

Figure $\xrightarrow[{pyridine}]{{C{H_3}COCl}}$ $P$ $\xrightarrow[{C{H_3}COOH}]{{B{r_2}}}Q\,\xrightarrow{{{H_3}{O^ + }}}R$