$Cu(II)$ halides are known except the iodide. The reason for it is that:
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All $Cu(II)$ halides are known except the iodine because $Cu^{2+}$ oxidizes iodine to iodine. $\ce{2Cu^{2+}+ 4I^{−1 }\rightarrow 2CuI_{(S)} + I_{2}}.$
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