MCQ
$Cu|Cu^{2+} (0.01\,M)||\, Cu^{2+}\,(0.1\,M)|\,Cu$ 

$E_{cell} = $ ?

  • A
    $\frac{RT}{2F}\,ln\,(0.1)$
  • $-\frac{RT}{2F}\,ln\,(0.1)$
  • C
    $\frac{RT}{F}\,ln\,(0.1)$
  • D
    $-\frac{RT}{F}\,ln\,(0.1)$

Answer

Correct option: B.
$-\frac{RT}{2F}\,ln\,(0.1)$
b
$E_{cell} = 0 - \frac{RT}{nF}\,ln\,Q$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Number of ambidentate ligands in a representative metal complex $\left[ M ( en )( SCN )_4\right]$ is $\text { [en }=\text { ethylenediamine }]$
The number of different chain isomers for $\mathrm{C}_7 \mathrm{H}_{16}$ is . . . . . . . 
Oxidation number of $N$ in ${(N{H_4})_2}S{O_4}$ is
$Cu^{2+}(aq.)$ does not undergo redox reaction with solution of
If $\left[ Cu \left( H _{2} O \right)_{4}\right]^{2+}$ absorbs a light of wavelength $600$ $nm$ for $d - d$ transition, then the value of octahedral crystal field splitting energy for $\left[ Cu \left( H _{2} O \right)_{6}\right]^{2+}$ will be $.....\,\times 10^{-21}\, J$. (Nearest Integer)

(Given : $h =6.63 \times 10^{-34} \,Js$ and $c =3.08 \times 10^{8} \,ms ^{-1}$ )

The uncertainty in momentum of an electron is $1 \times {10^{ - 5}}\,kg\,m/s$. The uncertainity in its position will be $(h = 6.63 \times {10^{ - 34}}\,Js)$
Assertion : $\Delta H$ and $\Delta E$ are almost same for the reaction $N_2 (g) + O_2 (g)  \rightleftharpoons  2NO(g)$
Reason : All reactants and products are gases.
From the ground state electronic configuration of the elements given below, pick up the one with highest value of second ionisation energy.
Match List $- I$ with List$-II.$

List $- I$ List $- II$
$(a)$ $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ $(i)$ $5.92 \,\mathrm{BM}$
$(b)$ $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ $(ii)$ $0 \,\mathrm{BM}$
$(c)$ $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}$ $(iii)$ $4.90\, \mathrm{BM}$
$(d)$ $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ $(iv)$ $1.73\, \mathrm{BM}$

Choose the correct answer from the options given below.

Product $(C)$ of the above reaction is