MCQ
CuSO4​⋅5H2​O is blue is colour while CuSO4​ is colourless due to:
  • A
    Presence of strong field ligand in CuSO4​⋅5H2​O.
  • B
    Due to absence of water (ligand), d - d transitions are not possible in CuSO4.
  • C
    Anhydrous undergoes d - d transitions due to crystal field splitting.
  • D
    Colour is lost due to unpaired electrons.

Answer

  1. Due to absence of water (ligand), d - d transitions are not possible in CuSO4.

Explanation:

In CuSO4​⋅5H2​O, water acts as ligand and causes crystal filed splitting. This makes d - d transitions possible. On the other hand, in CuSO4​, due to absence of ligand crystal filed splitting is not possible.

Hence no colour is observed.

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