MCQ
Cyclic hydrocarbon molecule A has all the carbon and hydrogens in a single plane. All the carbon-carbon bonds are of same length and less that $1.54\,\mathop A\limits^o $ but more than $1.34\,\mathop A\limits^o $. $C - C - C$ bond angle will be
  • ${120^o}$
  • B
    ${180^o}$
  • C
    ${100^o}$
  • D
    ${109^o}28'$

Answer

Correct option: A.
${120^o}$
a
$(a)$ Cyclic hydrocarbon in which all the carbon atoms are present in the same plane is benzene. In this $C - C$ bond length is $1.39\,\mathop A\limits^o $ which is more than $1.34\,\mathop A\limits^o $ but less than $1.54\,\mathop A\limits^o $. Hence bond angle is ${120^o}$ with $s{p^2}$ hybridization.

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$\begin{array}{*{20}{c}}
  {H\,\,\,\,H} \\ 
  {|\,\,\,\,\,\,\,\,|} \\ 
  {C = C} \\ 
  {|\,\,\,\,\,\,\,\,\,|} \\ 
  {H\,\,\,\,H} 
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