MCQ
Cycloalkane has the formula
- A${C_n}{H_{2n + 2}}$
- B${C_n}{H_{2n - 2}}$
- ✓${C_n}{H_{2n}}$
- D${C_{2n}}{H_2}$
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$2MnO_4^ - + 5{C_2}O_4^{2 - } + 16{H^ + } \to 2M{n^{2 + }} + 10C{O_2} + 8{H_2}O$
Here $20\,ml$ of $0.1\,M$ $KMn{O_4}$ is equivalent to