MCQ
$D$ -glucose and $D$ -fructose can be differentiated by
- AFehling solution
- BTollens reagent
- CBenedict test
- ✓$Br_2/H_2O$
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$n-$propyl bromide $\xrightarrow{{Na}}(A)\xrightarrow[{A{l_2}{O_3}/773\,K}]{{Cr{O_3}}}(B)\xrightarrow[{500\,K}]{{C{l_2}/UV}}(C)$
$n-$propyl bromide $\xrightarrow{{Na}}(A)\xrightarrow[{A{l_2}{O_3}/773\,K}]{{Cr{O_3}}}(B)$ $\xrightarrow[{}]{{C{H_3} - Cl/AlC{L_3}}}(D)\xrightarrow{{C{l_2}/hv}}(E)$
$(1)$ $2, 4-$Dinitrophenol
$(2)$ $4 -$ Nitrophenol
$(3)$ $2, 4, 5-$Trimethylphenol
$(4)$ Phenol
$(5)$ $3-$Chlorophenol
$Image$
is/are