MCQ
$D$ is a point on the side $BC$ of a $\triangle\text{ABC}$ such that $AD$ bisects $\triangle\text{BAC}$ then:
- A$CD > CA$
- B$BD = CD$
- C$BD > BA$
- ✓$BA > BD$
✓
Answer
Correct option: D.
$BA > BD$
Since, $\triangle\text{BAC}$ is bisected by $AD$, then $\triangle\text{BAD}$ is less than $\triangle\text{ABC},$ hence the side opposite $\triangle\text{ABC},$ i.e., $BA$ is greater than the side opposite to $\triangle\text{BAD}$ i.e.$, BD.$
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