MCQ
${d \over {dx}}({e^x}\log \sin 2x) = $
- ✓${e^x}(\log \sin 2x + 2\cot 2x)$
- B${e^x}(\log \cos 2x + 2\cot 2x)$
- C${e^x}(\log \cos 2x + \cot 2x)$
- DNone of these
$ = {e^x}\log \sin 2x + {e^x}2\cot 2x$$ = {e^x}(\log \sin 2x + 2\cot 2x).$
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