MCQ
${d \over {dx}}\left( {{{\cos }^{ - 1}}\sqrt {{{1 + \cos x} \over 2}} } \right) = $
  • A
    $1$
  • ${1 \over 2}$
  • C
    ${1 \over 3}$
  • D
    None of these

Answer

Correct option: B.
${1 \over 2}$
b
(b) $\frac{d}{{dx}}\left( {{{\cos }^{ - 1}}\sqrt {\frac{{1 + \cos x}}{2}} } \right) = \frac{d}{{dx}}\left[ {{{\cos }^{ - 1}}\left( {\cos \frac{x}{2}} \right)} \right] = \frac{1}{2}$.

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