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STD 12 - 5. continuity and differentiation — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 5. continuity and differentiation4 Marks
MCQ
${d \over {dx}}\left( {{{\log x} \over {\sin x}}} \right) = $
  • A
    ${{{{\sin x} \over x} - \log x.\cos x} \over {\sin x}}$
  • ✓
    ${{{{\sin x} \over x} - \log x.\cos x} \over {{{\sin }^2}x}}$
  • C
    ${{\sin x - \log x.\cos x} \over {{{\sin }^2}x}}$
  • D
    ${{{{\sin x} \over x} - \log x} \over {{{\sin }^2}x}}$
✓

Answer

Correct option: B.
${{{{\sin x} \over x} - \log x.\cos x} \over {{{\sin }^2}x}}$
b
(b) $\frac{d}{{dx}}\left( {\frac{{\log x}}{{\sin x}}} \right) = \frac{{\frac{{\sin x}}{x} - \log x.\cos x}}{{{{\sin }^2}x}}$.

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