d dx [ ^ - 1 1 - x 1 + x ] =

MCQ

${d \over {dx}}\left[ {{{\tan }^{ - 1}}\sqrt {{{1 - \cos x} \over {1 + \cos x}}} } \right] = $

A
$ - {1 \over 2}$
B
$0$
✓
${1 \over 2}$
D
$1$

✓

Answer

Correct option: C.

${1 \over 2}$

c
(c) $\frac{d}{{dx}}\left[ {{{\tan }^{ - 1}}\sqrt {\frac{{1 - \cos x}}{{1 + \cos x}}} } \right] = \frac{d}{{dx}}\left[ {{{\tan }^{ - 1}}\tan \frac{x}{2}} \right] = \frac{1}{2}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 5. continuity and differentiation→STD 12 - 5. continuity and differentiation — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

If matrix $A = \left[ {\begin{array}{*{20}{c}}
{\sin \theta }&{\cos ec\theta }&1\\
{\cos ec\theta }&1&{\sin \theta }\\
1&{\sin \theta }&{\cos ec\theta }
\end{array}} \right]$ is a non invertible matrix, then possible value of $'\theta'$ is

$($ where $n \in I)$

→

If ${a^2}{x^4} + {b^2}{y^4} = {c^6},$ then maximum value of $xy $ is

→

Let the set of all values of $p$, for which

$f(x)=\left(p^2-6 p+8\right)\left(\sin ^2 2 x-\cos ^2 2 x\right)+2(2-p) x+7$ does not have any critical point, be the interval $(a, b)$. Then $16 a b$ is equal to ..........

→

If $A$ and $B$ are two matrices such that $AB = A$ and $BA = B,$ then $B^2$ is equal to :

→

A relation $R$ is defined on $N$. Which of the following is the reflexive relation?

→

$\int_{\,0}^{\,2\pi } {|\sin x|\,dx = } $

→

The point which does not lie in the half $-$ plane $2x + 3y -12 < 0$ is:

→

The value of $\int\limits_0^1 {\frac{{{x^4}{{(1 - x)}^4}}}{{1 + {x^2}}}dx} $ is equal to

→

Out of $30$ consecutive integers$, 2$ are chosen at random. The probability that their sum is odd, is