MCQ
${d \over {dx}}(\sin 2{x^2})$ equals
  • $4x\cos \,(2{x^2})$
  • B
    $2\sin {x^2}\cos {x^2}$
  • C
    $4x\sin ({x^2})$
  • D
    $4x\sin ({x^2})\cos ({x^2})$

Answer

Correct option: A.
$4x\cos \,(2{x^2})$
a
(a) $\frac{d}{{dx}}(\sin 2{x^2}) = \cos 2{x^2}.\frac{d}{{dx}}2{x^2} = \cos 2{x^2}.4x = 4x.\cos 2{x^2}$.

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