d dx 1 + 2x 1 - 2x = - Vidyadip

MCQ

${d \over {dx}}\sqrt {{{1 + \cos 2x} \over {1 - \cos 2x}}} = $

A
${\sec ^2}x$
✓
$ - {\rm{cose}}{{\rm{c}}^2}x$
C
$2\,{\sec ^2}{x \over 2}$
D
$ - 2{\rm{cose}}{{\rm{c}}^2}{x \over 2}$

✓

Answer

Correct option: B.

$ - {\rm{cose}}{{\rm{c}}^2}x$

b
(b) $\frac{d}{{dx}}\sqrt {\frac{{1 + \cos 2x}}{{1 - \cos 2x}}} = \frac{d}{{dx}}\cot x = - {\rm{cose}}{{\rm{c}}^2}x$.

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