MCQ
${d \over {dx}}\sqrt {{{1 - \sin 2x} \over {1 + \sin 2x}}} = $
- A${\sec ^2}x$
- ✓$ - {\sec ^2}\left( {{\pi \over 4} - x} \right)$
- C${\sec ^2}\left( {{\pi \over 4} + x} \right)$
- D${\sec ^2}\left( {{\pi \over 4} - x} \right)$
$ = \frac{{1 - \tan x}}{{1 + \tan x}} = \tan \left( {\frac{\pi }{4} - x} \right) $
$\Rightarrow \frac{{dy}}{{dx}} = - {\sec ^2}\left( {\frac{\pi }{4} - x} \right)$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List $I$ | List $II$ |
| $P.$ Let $y(x)=\cos \left(3 \cos ^{-1} x\right), x \in[-1,1], x \neq \pm \frac{\sqrt{3}}{2}$. Then $\frac{1}{y(x)}\left\{\left(x^2-1\right) \frac{d^2 y(x)}{d x^2}+x \frac{d y(x)}{d x}\right\}$ equals | $1.$ $1$ |
| $Q.$ Let $A_1, A_2, \ldots \ldots, A_n(n>2)$ be the vertices of a regular polygon of $n$ sides with its centre at the origin. Let $\vec{a}_k$ be the position vector of the point $A_k, k=1,2, \ldots, n$. If $\left|\sum_{k=1}^{n-1}\left(\overrightarrow{a_k} \times \overrightarrow{a_{k+1}}\right)\right|=\left|\sum_{k=1}^{n-1}\left(\overrightarrow{a_k} \cdot \overrightarrow{a_{k+1}}\right)\right|$, then the minimum value of $n$ is | $2.$ $2$ |
| $R.$ If the normal from the point $P(h, 1)$ on the ellipse $\frac{x^2}{6}+\frac{y^2}{3}=1$ is perpendicular to the line $x+y=8$, then the value of $h$ is | $3.$ $8$ |
| $S.$ Number of positive solutions satisfying the equation $\tan ^{-1}\left(\frac{1}{2 x+1}\right)+\tan ^{-1}\left(\frac{1}{4 x+1}\right)=\tan ^{-1}\left(\frac{2}{x^2}\right)$ is | $4.$ $9$ |
Codes: $ \quad P \quad Q \quad R \quad S $
($A$) There are infinitely many functions from $S$ to $T$
($B$) There are infinitely many strictly increasing functions from $\mathrm{S}$ to $\mathrm{T}$
($C$) The number of continuous functions from $\mathrm{S}$ to $\mathrm{T}$ is at most $120$
($D$) Every continuous function from $\mathrm{S}$ to $\mathrm{T}$ is differentiable