d dx ( x^2 + x)^4 = - Vidyadip

MCQ

${d \over {dx}}{({x^2} + \cos x)^4} = $

A
$4({x^2} + \cos x)(2x - \sin x)$
B
$4{({x^2} - \cos x)^3}(2x - \sin x)$
✓
$4{({x^2} + \cos x)^3}(2x - \sin x)$
D
$4{({x^2} + \cos x)^3}(2x + \sin x)$

✓

Answer

Correct option: C.

$4{({x^2} + \cos x)^3}(2x - \sin x)$

c
(c) $\frac{d}{{dx}}{[{x^2} + \cos x]^4} = 4{[{x^2} + \cos x]^3}[2x - \sin x]$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

If $sin (xy) + cos (xy) = 0$ then $\frac{{dy}}{{dx}}=$

For any real number $x$, let $[ x ]$ denote the largest integer less than equal to $x$. Let $f$ be a real valued function defined on the interval $[-10,10]$ by $f(x)=\left\{\begin{array}{cl}x-[x], & \text { if }(x) \text { is odd } \\ 1+[x]-x & \text { if }(x) \text { is even }\end{array}\right.$ Then the value of $\frac{\pi^{2}}{10} \int_{-10}^{10} f(x) \cos \pi x d x$ is.

If $n$ is a positive integer and $\omega \neq 1$ is a cube root of unity, the number of possible values of $\left|e^{\sum \limits_{k=0}^n C_k \omega^k}\right|$ is

$\mathop {\lim }\limits_{x \to 0} \left[ {\frac{{{e^x} - {e^{\sin x}}}}{{x - \sin x}}} \right]$ is equal to

In a triangle $\tan A + \tan B + \tan C = 6$ and $\tan A\tan B = 2,$ then the values of $\tan A,\,\,\tan B$ and $\tan C$ are

In order to get at least once a head with probability $ \ge 0.9,$ the number of times a coin needs to be tossed is

The angle bisectors $B D$ and $C E$ of a $\triangle A B C$ are divided by the incentre $I$ in the ratios $3: 2$ and $2: 1$ respectively. Then, the ratio in which $I$ divides the angle bisector through $A$ is

Given that the term of the expansion $(x^{1/3} - x^{-1/2})^{15}$ which does not contain $x$ is $5\, m$ where $m \in N$, then $m =$

Let $x_1,x_2,.........,x_{100}$ are $100$ observations such that $\sum {{x_i} = 0,\,\sum\limits_{1 \leqslant i \leqslant j \leqslant 100} {\left| {{x_i}{x_j}} \right|} } = 80000\,\& $ mean deviation from their mean is $5,$ then their standard deviation, is-

If ${\sin ^{ - 1}}\frac{1}{3} + {\sin ^{ - 1}}\frac{2}{3} = {\sin ^{ - 1}}x,$ then $ x$ is equal to