d dx ( x^2 + x)^4 = - Vidyadip

MCQ

${d \over {dx}}{({x^2} + \cos x)^4} = $

A
$4({x^2} + \cos x)(2x - \sin x)$
B
$4{({x^2} - \cos x)^3}(2x - \sin x)$
✓
$4{({x^2} + \cos x)^3}(2x - \sin x)$
D
$4{({x^2} + \cos x)^3}(2x + \sin x)$

✓

Answer

Correct option: C.

$4{({x^2} + \cos x)^3}(2x - \sin x)$

c
(c) $\frac{d}{{dx}}{[{x^2} + \cos x]^4} = 4{[{x^2} + \cos x]^3}[2x - \sin x]$.

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