Question
$\triangle ABC$ is enlarged, with a scale factor $5.$ Find $:\text{BC}, \text{B'C'} = 16\ cm$

Answer

$\frac{\text { Image length }}{\text { Actual length }}=\text { Scale factor }$
$\frac{ B ^{\prime} C ^{\prime}}{ BC }=5$
$\Rightarrow \text{BC}=\frac{16}{5}$
$\Rightarrow \text{BC} =3.2\ cm .$

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