MCQ
David is observing his image in a plane mirror. The distance between the mirror and his image is $4 m.$ If he moves $1 m$ towards the mirror, then the distance between David and his image will be.
- A$3 m$
- B$5 m$
- ✓$6 m$
- D$8 m$
✓
Answer
Correct option: C.
$6 m$
$6$ mIn the case of a plane mirror, the distance between the object and the mirror $(d_1)$ is same as the distance between the image and the mirror $(d_2).$
Given,
Distance between the mirror and David’s image, $d_2 = 4 m$
Therefore, $d_1 = d_2 = 4 m$
If David moves $1 m$ towards the mirror, then $d_1 = 4 − 1 = 3 m$
Again, $d_1 = d_2 = 3 m$
$\therefore$, the distance between David and his image is $d_1 + d_2 = 3 + 3 = 6 m$
Given,
Distance between the mirror and David’s image, $d_2 = 4 m$
Therefore, $d_1 = d_2 = 4 m$
If David moves $1 m$ towards the mirror, then $d_1 = 4 − 1 = 3 m$
Again, $d_1 = d_2 = 3 m$
$\therefore$, the distance between David and his image is $d_1 + d_2 = 3 + 3 = 6 m$
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