MCQ
Decreasing order of bond angle is
- ✓$BeCl_2 > NO_2 > SO_2$
- B$BeCl_2 > SO_2 > NO_2$
- C$SO_2 > BeCl_2 > NO_2$
- D$SO_2 > NO_2 > BeCl_2$
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The frequency of the wave is $\mathrm{x} \times 10^{19} \mathrm{~Hz}$. $x=$ . . . . (nearest integer)