Question
Define centripetal force. A cyclist speeding at 18km/ hr on a level road takes a sharp circular turn of radius 3m without reducing the speed. The coefficient of static friction is 0.1. Will the cyclist slip while taking the turn?
✓
Answer
The force on the body towards the centre while it is moving is a circular path. The condition for the cyclist not to slip is $\text{V}^2\leq\mu_\text{s}\times\text{R}\times\text{g}$ $\text{V}^2\leq0.1\times3\times9.8$ $\text{V}^2=2.94\text{m}^2/\text{s}^2$ But the speed of the cyclist is $18\text{km}/\text{hr}=5\text{m}/\text{s}$ $\therefore\text{V}^2=25\text{m}^2/\text{s}^2$ $\therefore$ The condition is not obeyed $\therefore$ The cyclist will slip.
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