Gujarat BoardEnglish MediumSTD 12 SciencePhysicsAtoms2 Marks
Question
Define the distance of closest approach.
✓
Answer
The minimum distance upto which an energetic $\alpha$-particle travelling directly towards a nucleus can move before coming to rest and then retracing its path is known as distance of closest approach. $F=\frac{1}{4 \pi \in_0} \frac{(2 e)(Ze)}{r^2}$ Where $r$ is the distance of $\alpha$-particle from nucleus.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.