Question
Define the SI unit of the magnetic field.
✓
Answer
→The SI unit of magnetic field is Tesla (T)
→The magnetic force $F _m=q \cup B \sin \theta$ $B =\frac{ F _m}{q v}\left(\theta=90^{\circ}\right)$
→When the force acting on a unit charge ( 1 C) moving perpendicular to magnetic field with a speed of $1 m / s$ is 1 N then the magnitude of magnetic field $(\vec{B})$ is to be $1 T$.
→Tesla is a large unit of magnetic field. The smaller unit (CGS) is called gauss.
$1 \text { gauss }=10^{-4} T$
→The earth's magnetic field is about $3.6 \times 10^{-5} T$
→The magnetic force $F _m=q \cup B \sin \theta$ $B =\frac{ F _m}{q v}\left(\theta=90^{\circ}\right)$
→When the force acting on a unit charge ( 1 C) moving perpendicular to magnetic field with a speed of $1 m / s$ is 1 N then the magnitude of magnetic field $(\vec{B})$ is to be $1 T$.
→Tesla is a large unit of magnetic field. The smaller unit (CGS) is called gauss.
$1 \text { gauss }=10^{-4} T$
→The earth's magnetic field is about $3.6 \times 10^{-5} T$
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