Question
  1. Derive an expression for the average power consumed in a series LCR circuit connected to a.c. source in which the phase difference between the voltage and the current in the circuit is $\phi$.
  2. Define the quality factor in an a.c. circuit. Why should the quality factor have high value in receiving circuits? Name the factors on which it depends.

Answer

  1. In a series LCR circuit.
Voltage $\text{v} = \text{v}_{m} \sin\omega\text{t}$
Current in the circuit is given by $\text{i} =\text{i}_{m} \sin\big(\omega\text{t} + \Phi\big)$
Therefore, the instantaneous power $p_i$ supplied by the source is $\text{p}_{i} = \text{vi} = \big(\text{V}_{m}\sin\omega\text{t}\big)\times[\text{i}_{m}\sin\big(\omega\text{t} + \phi\big)]$

$ =\frac{\text{v}_{m}\text{i}_{m}}{2}[cos\phi - cos\big(2\omega\text{t} +\phi\big)]$
The average power over a cycle is given by the average of the two terms on the R.H.S.. It is only the second term which is time-dependent. Its average over a complete cycle is zero (the positive half of the cosine cancels the negative.
$\text{P}_{av}$
$ = \text{VI} \cos \phi$
  1. Quality factor: The ratio of the voltage drop (in a series LCR circuit) across the inductor (or capacitor) to the voltage drop across resistor under resonance conditions.
Reason: Selectivity (or sharpness of resonance) of the circuit becomes large.
Factors: depends on inductance , capacitance and resistance.

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