Question
Derive the relation between newton and dyne.
✓
Answer
Relation between newton and dyne :
$\begin{array}{l}1 N=1 kg x ms ^{-2}=1000 g \times 100 cm S ^{\sim}{ }^2 \\ 1 N=100000 g cm s ^{\prime 2} \\ 1 N=10^5 g cm s ^{-2} \\ 1 N=10^5 \quad\left[\therefore 1 \text { dyne }=1 g cm s ^{-2}\right]\end{array}$
$\begin{array}{l}1 N=1 kg x ms ^{-2}=1000 g \times 100 cm S ^{\sim}{ }^2 \\ 1 N=100000 g cm s ^{\prime 2} \\ 1 N=10^5 g cm s ^{-2} \\ 1 N=10^5 \quad\left[\therefore 1 \text { dyne }=1 g cm s ^{-2}\right]\end{array}$
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