Describe the nature of image formed when the object is placed at a distance of 20cm from a concave mirror of focal length 10cm.
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Hence, u = -20cm ; f = -10cm$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$ \Rightarrow\frac{1}{\text{v}}+\frac{1}{(-20)}=\frac{1}{-10}$
$ \Rightarrow\frac{1}{\text{v}}= \frac{1}{-20}-\frac{1}{-10}=\frac{1}{-20}$
$\therefore\text{v}=-20\text{cm}$
So, image will be real and inverted.
$ \Rightarrow\frac{1}{\text{v}}+\frac{1}{(-20)}=\frac{1}{-10}$
$ \Rightarrow\frac{1}{\text{v}}= \frac{1}{-20}-\frac{1}{-10}=\frac{1}{-20}$
$\therefore\text{v}=-20\text{cm}$
So, image will be real and inverted.
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