Question
Determine if f defined by $f(x)=\left\{\begin{array}{c}x^2 \sin \frac{1}{x}, \text { if } x \neq 0 \\ 0, \text { if } x=0\end{array}\right.$ is a continuous function?
$\left[ {\because \sin \frac{1}{x}{\text{lies between - 1 and 1}}} \right]$
Also f(0) = 0
Since, $\mathop {\lim }\limits_{x \to 0} f\left( x \right) = f\left( 0 \right)$ therefore, the function f is continuous at x = 0.
Also,when $x\ne0$ ,then f(x) is the product of two continuous functions and hence Continuous.Hence,f(x) is continuous everywhere.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.