Question
Determine if the $33, 121, 9, 96$ are in proportion.
✓
Answer
$33 : 121$ $=\frac{33}{121}=\frac{33 \div 11}{121 \div 11}$[$\therefore$$H.C.F.(33, 121) = 11]$
$=\frac{3}{11}$$ = 3 : 11$
$9 : 96$ $=\frac{9}{96}=\frac{9 \div 3}{96 \div 3}$[$\therefore$$H.C.F.(9, 96) = 3]$
$=\frac{3}{32}$ $= 3 : 32$
$\because $ $3 : 11$ $\neq$ $3 : 32$
$\therefore$ $33, 121, 9, 96$ are not in proportion.
$=\frac{3}{11}$$ = 3 : 11$
$9 : 96$ $=\frac{9}{96}=\frac{9 \div 3}{96 \div 3}$[$\therefore$$H.C.F.(9, 96) = 3]$
$=\frac{3}{32}$ $= 3 : 32$
$\because $ $3 : 11$ $\neq$ $3 : 32$
$\therefore$ $33, 121, 9, 96$ are not in proportion.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Without actual division show that of the following number is divisible by 5:
50005
50005
From figure, list the points which are:
$i.\ $In the interior of $\angle\text{P}$
$ii.\ $In the exterior of $\angle\text{P}$
$iii.\ $Lie on $\angle\text{P}$
→$i.\ $In the interior of $\angle\text{P}$
$ii.\ $In the exterior of $\angle\text{P}$
$iii.\ $Lie on $\angle\text{P}$
Draw a line segment of length $9.5\ cm$ and construct its perpendicular bisector.
→The cost price of $23 TV$ sets is $Rs. 570055$. Find the cost of each such set.
→Express the following ratios in the simplest form:
$36 : 90$
→$36 : 90$
Present age of father is $42$ years and his son is $14$ years. Find the ratio of age of the father to the age of son, when son was $12$ years old.
→Convert $2009$ paise to rupees and express the result as a mixed fraction.
→The ratio of the number of male and female workers in a textile mill is $5 : 3$. If there are $115$ male workers, what is the number of female workers in the mill?
→A box of medicine tablets contains $2,00,000$ tablets each weighing $20mg$. what is the total weight of all the tablets in the box in grams? in kilograms?
→Divide, and find out the quotient and remainder. Check your answer. $16135 ÷ 875$
→