Question
Determine the validity of the following arguments using the direct method of truth table:
$\sim P\ v \sim Q$
$Q$
$\therefore \sim P$

Answer

Combining the two bases of this argument as a whole, the argument will be as follows:
$(\sim P\ v \sim Q)\ \&\ Q$
$\therefore \sim P$
Truth Table:
  Support Statement The resulting statement
  $1$ $2$ $3$ $4$ $5$ $6$ $7$
$P$ $Q$ $\sim P$ $\sim Q`$ $\sim P\ v \sim Q$ $(\sim\ P\ v\ \sim\ Q)\ \&\ Q$ $\sim P$
$1$ $T$ $T$ $F$ $F$ $F$ $F$ $F$
$2$ $T$ $F$ $F$ $T$ $T$ $F$ $F$
$3$ $F$ $T$ $T$ $F$ $T$ $T^*$ $T^*$
$4$ $F$ $F$ $T$ $T$ $T$ $F$ $T$
  $1(\sim )$ $2(\sim )$ $3, 4(v)$ $5, 2(\&)$ As $3$
Judgment of the authenticity of the argument: In the above fact sheet, seven full pillars have been formed. In which the column no. $6th$ base statement and column no. $7$ is the presentation of the result statement. Out of the total four rows of the truth table, only row no. The base statement truth in $3$ is $‘T’$ and the resulting statement truth in the same row is $‘T’.$ Hence this argument is standard.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free