Question
Determine whether $f(x)=-\frac{\pi}{2}+$ sin x is increasing or decreasing on $\left(-\frac{\pi}{3}, \frac{\pi}{3}\right)$

Answer

Given: $f(x)=-\frac{x}{2}+\sin x$
$\Rightarrow f^{\prime}(x)=-\frac{1}{2}+\cos x$
Now $ x \in\left(-\frac{\pi}{3}, \frac{\pi}{3}\right)$
$\Rightarrow-\frac{\pi}{3} < x < \frac{\pi}{3}$
$\Rightarrow \cos \left(-\frac{\pi}{3}\right) < \cos x < \cos \frac{\pi}{3}$
$\Rightarrow \cos \left(\frac{\pi}{3}\right) < \cos x < \cos \frac{\pi}{3}$
$\Rightarrow \frac{1}{2} < \cos x < \frac{1}{2}$
$\Rightarrow-\frac{1}{2}+\cos x > 0$
$\Rightarrow f^{\prime}(x) > 0 $
Hence, $f(x)$ is an increasing function on $\left(-\frac{\pi}{3}, \frac{\pi}{3}\right)$.

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