Question
Devide The Following :
$\left(3 x-3 x^2-12+x^4+x^3\right) \div\left(2+x^2\right)$
$\left(3 x-3 x^2-12+x^4+x^3\right) \div\left(2+x^2\right)$
✓
Answer
$\left(3 x-3 x^2-12+x^4+x^3\right) \div\left(2+x^2\right)$
Write the dividend in descending order of their indices.
$\left(x^4+x^3-3 x^2+3 x-12\right) \div\left(x^2+2\right)$
$\therefore \text { Quotient }=x^2+x-5$
$\text { Remainder }=x-2$
Write the dividend in descending order of their indices.
$\left(x^4+x^3-3 x^2+3 x-12\right) \div\left(x^2+2\right)$
$\therefore \text { Quotient }=x^2+x-5$
$\text { Remainder }=x-2$
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