ધારો કે $A$ એ $3 \times 3$ વાસ્તવિક શ્રેણિક છે કે જેથી $A \left(\begin{array}{l}1 \\ 1 \\ 0\end{array}\right)=\left(\begin{array}{l}1 \\ 1 \\ 0\end{array}\right) ; A \left(\begin{array}{l}1 \\ 0 \\ 1\end{array}\right)=\left(\begin{array}{c}-1 \\ 0 \\ 1\end{array}\right)$ અને $A \left(\begin{array}{l}0 \\ 0 \\ 1\end{array}\right)=\left(\begin{array}{l}1 \\ 1 \\ 2\end{array}\right)$. જો $X =\left( x _{1}, x _{2}, x _{3}\right)^{ T }$ અને $I$ એ કક્ષા $3$ વાળો એકમ શ્રેણિક હોય, તો સંહતિ $( A -2 I ) X =\left(\begin{array}{l}4 \\ 1 \\ 1\end{array}\right)$ ને $............. $
A
એક પણ ઉકેલ નથી
B
આનંત ઉકેલ છે
C
અનન્ય ઉકેલ છે
D
બરાબર બે ઉકેલ છે
JEE MAIN 2022, Medium
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D
બરાબર બે ઉકેલ છે
$A =\left[\begin{array}{lll} a _{1} & b _{1} & c _{1} \\ a _{2} & b _{2} & c _{2} \\ a _{3} & b _{3} & c _{3}\end{array}\right]$$A \left[\begin{array}{l}0 \\ 0 \\ 1\end{array}\right]=\left[\begin{array}{l} c _{1} \\ c _{2} \\ c _{3}\end{array}\right]=\left[\begin{array}{l}1 \\ 1 \\ 2\end{array}\right]$
$\Rightarrow c _{1}=1, c _{2}=1, c _{3}=2$
$A \left[\begin{array}{l}1 \\ 0 \\ 1\end{array}\right]=\left[\begin{array}{l} c _{1}+ a _{1} \\ c _{2}+ a _{2} \\ c _{3}+ a _{3}\end{array}\right]=\left[\begin{array}{c}-1 \\ 0 \\ 1\end{array}\right]$
$\Rightarrow a _{1}=-2, a _{2}=-1, a _{3}=-1$
$A \left[\begin{array}{l}1 \\ 1 \\ 0\end{array}\right]=\left[\begin{array}{l} a _{1}+ b _{1} \\ a _{2}+ b _{2} \\ a _{3}+ b _{3}\end{array}\right]=\left[\begin{array}{l}1 \\ 1 \\ 0\end{array}\right]$
$\Rightarrow b _{1}=3, b _{2}=2, b _{3}=1$
$\Rightarrow \quad A =\left[\begin{array}{lll}-2 & 3 & 1 \\ -1 & 2 & 1 \\ -1 & 1 & 2\end{array}\right]$
$\Rightarrow A -2 I =\left[\begin{array}{ccc}-4 & 3 & 1 \\ -1 & 0 & 1 \\ -1 & 1 & 0\end{array}\right]$
$| A -2 I |=0$
Now, $\left[\begin{array}{lll}-4 & 3 & 1 \\ -1 & 0 & 1 \\ -1 & 1 & 0\end{array}\right]\left[\begin{array}{l} x _{1} \\ x _{2} \\ x _{3}\end{array}\right]=\left[\begin{array}{l}4 \\ 1 \\ 1\end{array}\right]$
$-4 x_{1}+3 x_{2}+x_{3}=4 \quad \ldots .$ ($1$)
$- x _{1}+ x _{3}=1 \ldots .$ ($2$)
$- x _{1}+ x _{2}=1 \ldots .$ ($2$)
$(1) -[(2)+3(3)]$
$0=0 \Rightarrow$ infinite solutions
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જો $a, b, c,$ એ શૂન્યતર સંકર સંખ્યા છે કે જે $a^2 + b^2 + c^2 = 0$ અને $\left| {\begin{array}{*{20}{c}}
{{b^2} + {c^2}}&{ab}&{ac}\\
{ab}&{{c^2} + {a^2}}&{bc}\\
{ac}&{bc}&{{a^2} + {b^2}}
\end{array}} \right| = k{a^2}{b^2}{c^2},$ નું પાલન કરે છે તો $k$ મેળવો.
સમીકરણની સંહતિ $\begin{array}{l}\alpha x + y + z = \alpha - 1\\x + \alpha y + z = \alpha - 1\\x + y + \alpha z = \alpha - 1\end{array}$ નો ઉકેલ ખાલીગણ હોય તો $\alpha $ કિમત મેળવો.
ધારોકે $P =\left[\begin{array}{ccc}3 & -1 & -2 \\ 2 & 0 & \alpha \\ 3 & -5 & 0\end{array}\right],$ જ્યાં $\alpha \in R .$ ધારોકે શ્રેણિક $Q =\left[ q _{ ij }\right]$ એ કોઈક શૂન્યતર $k \in R$ માટે $PQ = kI _{3}$ નું, સમાધાન કરે છે. તો $q _{23}=-\frac{ k }{8}$ અને $|Q|=\frac{k^{2}}{2}$ હોય, તો $\alpha^{2}+k^{2}=.........$