Question
Difference between two types of sulphur atoms in $Na_2S_4O_6$ will be
✓
Answer
In $\mathrm{Na}_{2} \mathrm{S}_{4} \mathrm{O}_{6}$, the oxidation number of end sulphur atoms is +5 each and the oxidation number of middle sulphur atoms is 0 each.
The difference in the oxidation numbers of the two types of sulphur atoms is $5-0=0$.
The structure of the compound is given below:
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