$CH_3-CH = CH -CH_2 -CH_2 -CH(CH_3)_2$
$(A)$ $(B)\,\,\,(C)$ $(D)$ $(E)\,\,\,(F)$
arrange them in decreasing order of reactivity towards free radical substitution
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Element | Atomic mass |
| $A$ | $12.01$ |
| $B$ | $35.5$ |
$A$ and $B$ combine to form new substance $X$ . If $4\,moles$ of $B$ combine with $1\,mole$ of $A$ to give $1\,mole$ of $X,$ then weight of one mole of $X$ is ........... $\mathrm{g}$
Given $\Delta H$
$(i)\, Fe_2O_{3(s)}+3C_{(graphite)} \to 2Fe_{(s)} + 3CO_{(g)}$ $492\, kJ/mol$
$(ii)\, FeO_{(s)}+C_{(graphite)} \to Fe_{(s)} + CO_{(g)}$ $156\, kJ/mol$
$(iii)\, C_{(graphite)} + O_{2(g)} \to CO_{2(g)}$ $-393 \,kJ/mol$
$(iv)\, CO_{(g)} + \frac{1}{2}\, O_{2(g)} \to CO_{2(g)}$ $-283\, kJ/mol$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,} \\
{\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
{C{H_3} - C - C{H_2} - C - CN} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$ \mathrm{N}_2=3.0 \times 10^{-3} \mathrm{M}, \mathrm{O}_2=4.2 \times 10^{-3} \mathrm{M} \text { and } \mathrm{NO}=2.8 \times 10^{-3} \mathrm{M} . $
$ 2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
If $0.1 \mathrm{~mol} \mathrm{~L} \mathrm{~L}^{-1}$ of $\mathrm{NO}_{(\mathrm{g})}$ is taken in a closed vessel, what will be degree of dissociation ( $\alpha$ ) of $\mathrm{NO}_{(\mathrm{g})}$ at equilibrium?