Question
Differential equation $\frac{\text{dy}}{\text{dx}}=\text{y},\text{y}(0)=1$Function $\text{y}=\text{e}^\text{x}$
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$y d x+\left(x-y^2\right) d y=0$
$4 \frac{d x}{d y}+8 x=5 e^{-3 y}$